Documentation

Lean.Meta.Tactic.Simp.Main

Helper method for bootstrapping purposes. It disables arith if support theorems have not been defined yet.

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    Return true if e is of the form ofNat n where n is a kernel Nat literal

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          Try to use automatically generated congruence theorems. See mkCongrSimp?.

          Process the given congruence theorem hypothesis. Return true if it made "progress".

          Try to rewrite e children using the given congruence theorem

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                @[inline]
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                  def Lean.Meta.Simp.main (e : Lean.Expr) (ctx : Lean.Meta.Simp.Context) (usedSimps : optParam Lean.Meta.Simp.UsedSimps ) (methods : optParam Lean.Meta.Simp.Methods { pre := fun (e : Lean.Expr) => pure (Lean.Meta.Simp.Step.visit { expr := e, proof? := none, dischargeDepth := 0 }), post := fun (e : Lean.Expr) => pure (Lean.Meta.Simp.Step.done { expr := e, proof? := none, dischargeDepth := 0 }), discharge? := fun (x : Lean.Expr) => pure none }) :
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                    def Lean.Meta.Simp.dsimpMain (e : Lean.Expr) (ctx : Lean.Meta.Simp.Context) (usedSimps : optParam Lean.Meta.Simp.UsedSimps ) (methods : optParam Lean.Meta.Simp.Methods { pre := fun (e : Lean.Expr) => pure (Lean.Meta.Simp.Step.visit { expr := e, proof? := none, dischargeDepth := 0 }), post := fun (e : Lean.Expr) => pure (Lean.Meta.Simp.Step.done { expr := e, proof? := none, dischargeDepth := 0 }), discharge? := fun (x : Lean.Expr) => pure none }) :
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                      Return true if e is of the form (x : α) → ... → s = t → ... → False

                      Recall that this kind of proposition is generated by Lean when creating equations for functions and match-expressions with overlapping cases. Example: the following match-expression has overlapping cases.

                      def f (x y : Nat) :=
                        match x, y with
                        | Nat.succ n, Nat.succ m => ...
                        | _, _ => 0
                      

                      The second equation is of the form

                      (x y : Nat) → ((n m : Nat) → x = Nat.succ n → y = Nat.succ m → False) → f x y = 0
                      

                      The hypothesis (n m : Nat) → x = Nat.succ n → y = Nat.succ m → False is essentially saying the first case is not applicable.

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                          Tries to solve e using unifyEq?. It assumes that isEqnThmHypothesis e is true.

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                                See simpTarget. This method assumes mvarId is not assigned, and we are already using mvarIds local context.

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                                  Simplify the given goal target (aka type). Return none if the goal was closed. Return some mvarId' otherwise, where mvarId' is the simplified new goal.

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                                    Apply the result r for prop (which is inhabited by proof). Return none if the goal was closed. Return some (proof', prop') otherwise, where proof' : prop' and prop' is the simplified prop.

                                    This method assumes mvarId is not assigned, and we are already using mvarIds local context.

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                                        Simplify prop (which is inhabited by proof). Return none if the goal was closed. Return some (proof', prop') otherwise, where proof' : prop' and prop' is the simplified prop.

                                        This method assumes mvarId is not assigned, and we are already using mvarIds local context.

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                                            Simplify simp result to the given local declaration. Return none if the goal was closed. This method assumes mvarId is not assigned, and we are already using mvarIds local context.

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