Given three distinct (ordered) points $A$, $B$, $C$, this function returns whether they are collinear, i.e. whether the projective direction of the vector $\overrightarrow{AB}$ is the same as the projective direction of the vector $\overrightarrow{AC}$.
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Given three points $A$, $B$, $C$, return whether they are collinear: if at least two of them are equal, then they are considered collinear; if the three points are distinct, we use the earlier definition of colinarity for distinct points.
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Given three points $A$, $B$, $C$ and a real number $t$, if the vector $\overrightarrow{AC}$ is $t$ times the vector $\overrightarrow{AB}$, then $A$, $B$, and $C$ are collinear.
Given three points $A$, $B$, $C$, if the vector $\overrightarrow{AC}$ is a scalar multiple of the vector $\overrightarrow{AB}$, then $A$, $B$, $C$ are collinear.
Given three points $A$, $B$, $C$ such that $B \neq A$, we have $A$, $B$, $C$ are collinear if and only if the vector $\overrightarrow{AC}$ is a scalar multiple of the vector $\overrightarrow{AB}$.
For any two points $A$ and $C$, the points $A$, $A$, $C$ are collinear.
Given three points $A$, $B$, and $C$, if $A$, $B$, $C$ are collinear (in that order), then $A$, $C$, $B$ are collinear (in that order); in other words, swapping the last two of the three points does not change the definition of colinarity.
Given three points $A$, $B$, and $C$, if $A$, $B$, $C$ are collinear (in that order), then $B$, $A$, $C$ are collinear (in that order); in other words, in the definition of colinarity, swapping the first two of the three points does not change property of the three points being collinear.
Given four points $A$, $B$, $C$, $D$ with $B \neq A$, if $A$, $B$, $C$ are collinear, and if $A$, $B$, $D$ are collinear, then $A$, $C$, $D$ are collinear.
Given three points $A$, $B$, $C$, if they are not collinear, then they are pairwise distinct, i.e. $C \neq B$, $A \neq C$, and $B \neq A$.
If $A$, $B$, $C$ are three points which lie on a ray, then they are collinear.
If $A$, $B$, $C$ are three points which lie on a segment, then they are collinear.
There exists three points $A$, $B$, $C$ on the plane such that they are not collinear.