Geometry Problems of 48th International Mathematical Olympiad (2007) #
Problem 2 #
Consider five points $A$, $B$, $C$, $D$, $E$ such that $ABCD$ is a parallelogram and $BCED$ is a cyclic quadrilateral. Let $l$ be a line passing through $A$, and let $l$ intersect segment $DC$ and line $BC$ at points $F$ and $G$, respectively. Suppose that $EF$ = $EG$ = $EC$. Prove that $l$ is the bisector of angle $DAB$.
- A : P
- B : P
- C : P
- D : P
- E : P
- hp : { point₁ := s.A, point₂ := s.B, point₃ := s.C, point₄ := s.D }.IsPrgND
- ω : EuclidGeom.Circle P
- hbo : EuclidGeom.lies_on s.B s.ω
- hco : EuclidGeom.lies_on s.C s.ω
- heo : EuclidGeom.lies_on s.E s.ω
- hdo : EuclidGeom.lies_on s.D s.ω
- l : EuclidGeom.Line P
- ha : EuclidGeom.lies_on s.A s.l
- F : P
- hf : EuclidGeom.lies_on s.F s.l
- hfdc : EuclidGeom.lies_int s.F { source := s.D, target := s.C }
- G : P
- hg : EuclidGeom.lies_on s.G s.l
- hglbc : EuclidGeom.lies_on s.G (LIN s.B s.C (_ : { point₁ := s.A, point₂ := s.B, point₃ := s.C, point₄ := s.D }.point₃ ≠ { point₁ := s.A, point₂ := s.B, point₃ := s.C, point₄ := s.D }.point₂))
Instances For
$C$ ≠ $B$ since $ABCD$ is a nondegenerate parallelogram.
Equations
- (_ : EuclidGeom.PtNe e.C e.B) = (_ : Fact (e.C ≠ e.B))
$D$ ≠ $C$ since $ABCD$ is a nondegenerate parallelogram.
Equations
- (_ : EuclidGeom.PtNe e.D e.C) = (_ : Fact (e.D ≠ e.C))
$D$ ≠ $A$ since $ABCD$ is a nondegenerate parallelogram.
Equations
- (_ : EuclidGeom.PtNe e.D e.A) = (_ : Fact (e.D ≠ e.A))
$B$ ≠ $A$ since $ABCD$ is a nondegenerate parallelogram.
Equations
- (_ : EuclidGeom.PtNe e.B e.A) = (_ : Fact (e.B ≠ e.A))
$F$ ≠ $C$ since $F$ lies in the interior the segment $DC$.
Equations
- (_ : EuclidGeom.PtNe e.F e.C) = (_ : Fact (e.F ≠ e.C))
Rename line $BC$ as lbc
.
Instances For
Rename line $DC$ as ldc
.
Instances For
Rename the nondegenerate parallelogram $ABCD$ as prg
.
Equations
- e.prg = EuclidGeom.ParallelogramND.mk_pt_pt_pt_pt e.A e.B e.C e.D (_ : { point₁ := e.A, point₂ := e.B, point₃ := e.C, point₄ := e.D }.IsPrgND)
Instances For
$B$, $C$ and $D$ are not collinear since $ABCD$ is a nondegenerate parallelogram.
$C$, $D$ and $A$ are not collinear since $ABCD$ is a nondegenerate parallelogram.
$C$, $D$ and $A$ are not collinear since $ABCD$ is a nondegenerate parallelogram.
$B$ lies on line $BC$.
$C$ lies on line $BC$.
$D$ lies on line $DC$.
$C$ lies on line $DC$.
$A$ lies on line $AB$.
$B$ lies on line $AB$.
$D$ lies on line $DA$.
$A$ lies on line $DA$.
$F$ lies on line $DC$ since $F$ lies in the interior the segment $DC$.
Line $DC$ is not equal to line $BC$ since $B$, $C$ and $D$ are not collinear.
Line $DC$ is not equal to line $AB$ since $A$, $B$ and $D$ are not collinear.
Line $DC$ is not equal to line $BC$ since $B$, $C$ and $D$ are not collinear.
Line $DC$ is parallel to line $AB$ since $ABCD$ is a nondegenerate parallelogram.
Line $DA$ is parallel to line $BC$ since $ABCD$ is a nondegenerate parallelogram.
$G$ ≠ $A$.
Equations
- (_ : EuclidGeom.PtNe e.G e.A) = (_ : Fact (e.G ≠ e.A))
$G$ ≠ $F$.
Equations
- (_ : EuclidGeom.PtNe e.G e.F) = (_ : Fact (e.G ≠ e.F))
$G$ ≠ $B$.
Equations
- (_ : EuclidGeom.PtNe e.G e.B) = (_ : Fact (e.G ≠ e.B))
$G$ ≠ $C$.
Equations
- (_ : EuclidGeom.PtNe e.G e.C) = (_ : Fact (e.G ≠ e.C))
$|EF| = |EC|$.
$F$ lies in the interior the segment $AG$ due to the conditions of parallel lines.
$C$ lies in the interior the segment $BG$ due to the conditions of parallel lines.
$E$ ≠ $B$.
Equations
- (_ : EuclidGeom.PtNe e.E e.B) = (_ : Fact (e.E ≠ e.B))
$E$ ≠ $C$.
Equations
- (_ : EuclidGeom.PtNe e.E e.C) = (_ : Fact (e.E ≠ e.C))
$E$ ≠ $D$.
Equations
- (_ : EuclidGeom.PtNe e.E e.D) = (_ : Fact (e.E ≠ e.D))
∠$CBE$ and ∠$CDE$ are congruent modulo π since $BCED$ is a cyclic quadrilateral.
$E$ is not lies on line $BC$.
$E$ is not lies on line $DC$.
$G$ is not lies on line $DC$.
Let $K$ be the midpoint of segment $CG$.
Equations
- e.K = { source := e.C, target := e.G }.midpoint
Instances For
Let $L$ be the midpoint of segment $FC$.
Equations
- e.L = { source := e.F, target := e.C }.midpoint
Instances For
$K$ ≠ $B$ since it is the midpoint of the nondegenerate segment $CG$.
Equations
- (_ : EuclidGeom.PtNe e.K e.B) = (_ : Fact (e.K ≠ e.B))
$K$ ≠ $C$ since it is the midpoint of the nondegenerate segment $CG$.
Equations
- (_ : EuclidGeom.PtNe e.K e.C) = (_ : Fact (e.K ≠ e.C))
$L$ ≠ $F$ since it is the midpoint of the nondegenerate segment $FC$.
Equations
- (_ : EuclidGeom.PtNe e.L e.F) = (_ : Fact (e.L ≠ e.F))
$L$ ≠ $C$ since it is the midpoint of the nondegenerate segment $FC$.
Equations
- (_ : EuclidGeom.PtNe e.L e.C) = (_ : Fact (e.L ≠ e.C))
$L$ ≠ $D$ since $L$ lies in the interior the segment $DC$.
Equations
- (_ : EuclidGeom.PtNe e.L e.D) = (_ : Fact (e.L ≠ e.D))
$K$ is the perpendicular foot from $E$ to line $BC$.
$L$ is the perpendicular foot from $E$ to line $DC$.
$K$ lies on line $BC$ since it is the perpendicular foot from $E$ to line $BC$.
$L$ lies on line $DC$ since it is the perpendicular foot from $E$ to line $DC$.
Rename nondegenerate ▵$KBE$ as KBE
.
Equations
- e.KBE = { val := { point₁ := e.K, point₂ := e.B, point₃ := e.E }, property := (_ : ¬EuclidGeom.Collinear e.K e.B { point₁ := e.K, point₂ := e.B, point₃ := e.E }.point₃) }
Instances For
Rename nondegenerate ▵$LDE$ as LDE
.
Equations
- e.LDE = { val := { point₁ := e.L, point₂ := e.D, point₃ := e.E }, property := (_ : ¬EuclidGeom.Collinear e.L e.D { point₁ := e.L, point₂ := e.D, point₃ := e.E }.point₃) }
Instances For
Rename nondegenerate ▵$KCE$ as KCE
.
Equations
- e.KCE = { val := { point₁ := e.K, point₂ := e.C, point₃ := e.E }, property := (_ : ¬EuclidGeom.Collinear e.K e.C { point₁ := e.K, point₂ := e.C, point₃ := e.E }.point₃) }
Instances For
Rename nondegenerate ▵$LCE$ as LCE
.
Equations
- e.LCE = { val := { point₁ := e.L, point₂ := e.C, point₃ := e.E }, property := (_ : ¬EuclidGeom.Collinear e.L e.C { point₁ := e.L, point₂ := e.C, point₃ := e.E }.point₃) }
Instances For
$|EK| / |EL| = |KC| / |LC|$.
▵$CGF$ is a isosceles triangle.
$l$ is the bisector of angle $DAB$.